All G.
asked 06/05/25Limit of a graph
Use the graph of the function f to state the value of each limit, if it exists. (If an answer does not exist, enter DNE.)
f(x) = x√(7-x^-2)
A) lim f(x) x→0−
B) lim f(x) x→0+
2 Answers By Expert Tutors
Looking at Doug C.'s graph, you can easily see that the graph never approaches 0 from either direction, therefore the limit does not exist from the left or from the right.
Thinking of this algebraically, you need to pick a point that is close to 0 on each side and see what value y is approaching. From the right, I'll use x = 0.1
Since we cannot take the square root of a negative, the graph does not exist at this point. From the left, we could use x = -0.1. which yields that same results.
So from either direction, the limit does not exist.
Billy M. answered 06/07/25
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f(x) = x√(7-x^-2)
A) lim f(x) x→0−
= 0
B) lim f(x) x→0+
= 0
Doug C.
Not sure this is correct? Numbers close to zero are not in the domain of the function because values like f(-.1) or f(.1) result in the square root of a negative number. desmos.com/calculator/si1hhwcctc06/08/25
Christina P.
06/10/25
Doug C.
Yep, that is what the graph suggests. Rewriting the function as x/|x| [sqrt(7x^2-1)] means that the domain can be found by solving 7x^2-1>0. So domain is {x| x< -1/sqrt(7) OR x> 1/sqrt(7)}. This means the function is not defined for the interval (-1/sqrt(7), 1/sqrt(7)) which includes the neighborhood around x = 0. By turning on complex mode on Desmos, the following graph reveals that as x->0, f(x) goes towards -i and +i: desmos.com/calculator/2crgiukatz06/10/25
Christina P.
06/12/25
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Mark M.
Did you graph the function so that you could use it? If not do so before asking for assistance.06/06/25