Find the area under 𝑦=5sin(𝑥) and above 𝑦=5cos(𝑥) for 𝜋≤𝑥≤2𝜋. (Note that this area may not be defined over the entire interval.)

Answer 1

5sinx = 5cosx; tanx = 1; x = 5π/4. Area A = ∫_π^5π/4(5sinx - 5cosx)dx = (- 5cosx - 5sinx)_π^5π/4 = 5√2 - 5

Answer 2

See the videa.