The functions f(x) and g(x) are differentiable. The function h(x) is defined as: h(x)=f(x)+g(x) If f(6)=9, f′(6)= – 4, g(6)= – 6, and g′(6)= – 3, what is h′(6)? Simplify any fractions. h′(6)=

Answer 1

Answer 2

Since h(x) = f(x)+g(x) and we need to find h'(6), step one is to find h'(x).

h'(x)=f'(x) + g'(x).

That means that h'(6) will equal f'(6)+g'(6)

h'(6)= -4+-3, which is -7.

Therefore, h'(6) will equal -7.

Answer 3

h(x)=f(x) + g(x)

h'(x)= f'(x) +g'(x)

h'(6)= f'(6)+g'(6)

h'(6)= -4-3

= -7

Hope that helps !!