Mark M. answered 12/03/24
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
∫ θ 4√(1 - θ2)dθ
Let u = 1 - θ2. Then du = -2θdθ. So, θdθ = -(1/2)du.
We have -(1/2) ∫ u1/4du = -(2/5)u5/4 + C = -(2/5)(1 - θ2)5/4 + C