Mark M. answered 11/21/24
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
If y = √(1 - x2), then y2 = 1 - x2. So, x2+ y2 = 1 (the circle centered at (0,0) with radius 1).
The graph of y = √(1-x2) is the upper half of the circle.
Translate 1 unit upward to obtain the graph of y = 1 + √(1-x2).
Between x = -1 and x = 1, the region is bounded above by the semicircle and below by the x-axis.
Divide the region into a semicircle of radius 1 and a rectangle (with length 2 and height 1).
∫(-1 to 1) [1 + √(1-x2)]dx = (Area of semicircle) + (Area of rectangle) = π/2 + 2