
Robert J. answered 04/08/13
Certified High School AP Calculus and Physics Teacher
f = 2[e^(4x/y)] - 2x
∂f/∂x = (8/y)[e^(4x/y)] - 2 = -8e^-8 - 2, at (2, -1)
∂f/∂y = -2(4x/y^2)e^(4x/y) = -16e^-8, at (2, -1)
Answer: ∇f = <∂f/∂x, ∂f/∂y> = <-8e^-8 - 2, -16e^-8>
--------
Attn: Use parenthesis correctly to avoid ambiguity.