
Hayden F.
asked 11/04/24Use the Midpoint Rule with the given value of n to approximate the integral. Round the answer to four decimal places. 10 x4 + 5 dx, n = 4 2
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Ryan H. answered 11/05/24
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M.D. Graduate - 10+ yrs College & AP Calculus Pre-Health STEM Tutor
- Calculate the Width of Each Subinterval: The interval [2,10][2, 10][2,10] has a total width of 10−2=810 - 2 = 810−2=8. Since n=4n = 4n=4, divide this interval into 4 subintervals, each of width:
- Δx= 8 / 4= 2
- Determine the Midpoints of Each Subinterval: The midpoints xi∗x_i^*xi∗ for each subinterval are:
- For the first subinterval [2,4], midpoint x1∗=3x_1^* = 3x1∗=3
- For the second subinterval [4,6], midpoint x2∗=5x_2^* = 5x2∗=5
- For the third subinterval [6,8], midpoint x3∗=7x_3^* = 7x3∗=7
- For the fourth subinterval [8,10], midpoint x4∗=9x_4^* = 9x4∗=9
- Evaluate the Function at Each Midpoint: Compute f(x)= x4+5 at each midpoint:
- f(3)=34+5=81+5=86f(3) =86
- f(5)=54+5=625+5=630f(5) = =630
- f(7)=74+5=2401+5=2406f(7) = =2406
- f(9)=94+5=6561+5=6566f(9) =6566
- Apply the Midpoint Rule: Using the Midpoint Rule, approximate the integral by:
- ∫210(x4+5) dx≈Δx⋅(f(x1∗)+f(x2∗)+f(x3∗)+f(x4∗)
- Substituting the values:
- ≈2⋅(86+630+2406+6566)
- Calculate the sum inside the parentheses:
- 86+630+2406+6566=968886 + 630 + 2406 + 6566 = 968886+630+2406+6566=9688
- Then, multiply by Δx\Delta
So, the approximate value of the integral is:
∫210 (x4+5) dx≈19376.00

Mark M.
How did you determine the interval was [2, 10]?
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11/05/24
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Mark M.
Review your post for accuracy.11/04/24