A lobster tank in a restaurant is 1.25 m long by 1 m wide by 90 cm deep. Water density is 1000kg/m^3. Find the water forces on each of the larger and smaller sides of the tank

Answer 1

To find the water forces on the sides of the tank:

1. Force on larger sides (1.25 m x 0.9 m):

Area = 1.25 m × 0.9 m = 1.125 m²

Average pressure =

Force = Pressure × Area = 4414.5 × 1.125 = 4966.31 N

2. Force on smaller sides (1 m x 0.9 m):

Area = 1 m × 0.9 m = 0.9 m²

Average pressure = 4414.5 Pa (same as above)

Force = Pressure × Area = 4414.5 × 0.9 = 3973.05 N

So, the forces on the larger and smaller sides are 4966.31 N and 39

73.05 N, respectively.