Calculus 1 homework question please help

Question

𝑓(𝑥)=(2𝑥^3−(3/𝑥)+5√x−𝜋)(ln(2sin(𝑥)−8cos(𝑥)))

Find f'(x)

I don't know how to use the derivative rules to find it

Answer 1

a = 2x³ - 3/x + 5√x - π

a = 2x³ - 3x^-1 + 5x^1/2 - π

a' = 6x² + 3x^-2 + (5/2)x^-1/2

b = ln(2sin(x) - 8cos(x))

b' = 1/(2sin(x) - 8cos(x))•[2cos(x) + 8sin(x)]

b' = (2cos(x) + 8sin(x))/(2sin(x) - 8cos(x)

b' = (cos(x) + 4sin(x))/(sin(x) - 4cos(x))

Put these together using the product rule to get f '(x).