fdx=a(2x^2+1)(3x^3-7)x=-1

Question

fdx=a(2x^2+1)(3x^3-7)x=-1

Answer 1

Assuming that you want the value of f'(-1) for f(x) = a(2x² + 1)(3x³ - 7):

f(x) = a(6x⁵ + 3x³ - 14x² - 7)

f'(x) = a(30x⁴ + 9x² - 28x)

f'(-1) = 67a