
Yefim S. answered 10/10/24
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Math Tutor with Experience
By parts: u = x; dv = secxtanxdx; du = dx; v = secx;
xsecxtanxdx = xsecx - ∫secxdx = xsecx - lnIsecx + tanxI + C
Rozhan F.
asked 10/10/24Evaluate the integral. (Remember to use absolute values where appropriate. Remember the constant of integration.)
x sec(x) tan(x) dx
Yefim S. answered 10/10/24
Math Tutor with Experience
By parts: u = x; dv = secxtanxdx; du = dx; v = secx;
xsecxtanxdx = xsecx - ∫secxdx = xsecx - lnIsecx + tanxI + C
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