
Ross M. answered 10/06/24
Math, Economics, and Data Science Tutor
There are different ways to evaluate the integral
To evaluate the integral we can use the product-to-sum identities to simplify
sin(a)sin(b)=(1/2)[cos(a−b)−cos(a+b)]
Applying this to our integral gives:
sin(x)sin(3x)=(1/2)[cos(2x)−cos(4x)].
Now we can rewrite the integral:
I=∫−∞∞(1/2)(cos(2x)/x2−cos(4x)/x2)dx
This can be split into two separate integrals:
Since ∫−∞∞cos(kx)/x^2dx=π∣k∣.
Now you can separately evaluate each integral and get the final result.
Hope this helps.
If you still have difficulties, let me know.