Parker C. answered • 09/16/24
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Miku F.
asked • 09/15/24Find the integral of 6/(square root(e^(2x)-4) dx
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Yefim S. answered • 09/15/24
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u2 = e2x - 4; 2udu = 2e2xdx = 2(u2 + 4)dx; dx = udu/(u2+ 4);
∫6dx/√(e2x - 4) = ∫6udu[/u(u2 + 4)] = 3tan-1(u/2) + C = 3tan-1(√(e2x - 4)/2) + C
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Miku F.
Why was arctan used instead of arcsecant ?09/15/24