Miku F.
asked • 09/15/24Find the integral of 6/(square root(e^(2x)-4) dx
More
2 Answers By Expert Tutors
Yefim S. answered • 09/15/24
Tutor
5
(20)
Math Tutor with Experience
u2 = e2x - 4; 2udu = 2e2xdx = 2(u2 + 4)dx; dx = udu/(u2+ 4);
∫6dx/√(e2x - 4) = ∫6udu[/u(u2 + 4)] = 3tan-1(u/2) + C = 3tan-1(√(e2x - 4)/2) + C
Still looking for help? Get the right answer, fast.
Ask a question for free
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Find an Online Tutor Now
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
Miku F.
Why was arctan used instead of arcsecant ?09/15/24