
Yefim S. answered 09/05/24
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a) v = π∫01[25 - (5 - 5√x)2]dx,
b) v = π∫05[25 - (5 - y2/25)2]dy
Natalie N.
asked 09/05/24Y=5√x , y=5, x=0
a)about the y=5
b)about the line x=5
Yefim S. answered 09/05/24
Math Tutor with Experience
a) v = π∫01[25 - (5 - 5√x)2]dx,
b) v = π∫05[25 - (5 - y2/25)2]dy
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