
Yefim S. answered 09/05/24
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Math Tutor with Experience
a) v = π∫04π[(4y+ 4)2 - (y2 + 4)2]dy
b) v = π∫016[(√x + 4)2 - (x/4 + 4)2]dx
Natalie N.
asked 09/05/24X=y^2 , y=x/4
a)about the line x=-4
b) about the line y=-4
Yefim S. answered 09/05/24
Math Tutor with Experience
a) v = π∫04π[(4y+ 4)2 - (y2 + 4)2]dy
b) v = π∫016[(√x + 4)2 - (x/4 + 4)2]dx
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