Yefim S. answered 08/28/24
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y' = 2x; at x = 5 y' = 10. Equation of tangent line: y = 25 + 10(x - 5); y = 10x - 25; x = y/10 + 2.5 and y = √x;
Area A = ∫025(y/10 + 2.5 - √y)dy = (y2/20 + 2.5y - 2/3y3/2)025 = 125/4 + 62.5 - 250/3 = 125/12