Mark M. answered 08/29/24
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
The curves intersect when x2 - 2x = 3x + 6.
x2 - 5x - 6 = 0
(x - 6)(x + 1) = 0 So, x = -1 or 6.
Draw a diagram. You should see that the region is bounded above by the line with equation y = 3x + 6 and below by the parabola with equation y = x2 - 2x.
Area = ∫(-1 to 6) [3x + 6 - (x2 - 2x)]dx = ∫(-1 to 6) [-x2 + 5x + 6]dx =
[(-1/3)x3 + (5/2)x2 + 6x](-1 to 6) = (-72 + 90 + 36) - (1/3 + 5/2 - 6) = 60 - 1/3 - 5/2 = 57.1666