3√(125x14/y3)
The denominator is already a perfect cube (y3). Factor the numerator looking for other perfect cubes:
125 = 53
x14 = (x4)3*x2
So we have:
3√(125x14/y3)
= 3√(53*(x4)3*x2/y3)
= 3√53 * 3√(x4)3 * 3√x2 / 3√y3
= (5x4/y)* 3√x2
