Thomas K. answered 08/13/24
Top qualified Calculus Tutor| AP Calculus AB/BC, College Calc| 15+ yr
I assume that your function is f(x) = x^2 * e^(13x) ?!
Then, f'(x) = 2x*e^(13x) + 13e^(13x) * x^2 = x*e^(13x)*(2+13x) = 0
CN: x= - 2/13, x=0
check f' values, so we know inc/dec [Using 1st derivative test]
f'(-1) = -2*e^(-13)+13*e^(-13)*1 = 11*e^-11 >0 =>inc
f'(-.0000001) =-.00000019999996 <0 => dec
f'(1) = 6636200.88 >0 => inc
Hence, (-inf, -2/13) , (-2/13, 0), (0,inf) are important intervals
Inc: (-inf, -2/13) U (0,inf)
Dec: (-2/13, 0)
Doug C.
Actually -2/13 ?08/12/24