
Mark M. answered 08/13/24
Mathematics Teacher - NCLB Highly Qualified
There is only one inflection point, (0, 7)
Novalee S.
asked 08/12/24Consider the function 𝑓(𝑥)= 12𝑥^5 + 75x^4 - 120𝑥x^3 + 7.
𝑓(𝑥) has inflection points at (reading from left to right) x = D, E, and F
where D is
and E is
and F is
Mark M. answered 08/13/24
Mathematics Teacher - NCLB Highly Qualified
There is only one inflection point, (0, 7)
Thomas K. answered 08/13/24
Top qualified Calculus Tutor| AP Calculus AB/BC, College Calc| 15+ yr
𝑓(𝑥)= 12𝑥^5 + 75x^4 - 120𝑥x^3 + 7
f' = 60x^4 + 300x^3 -360x^2
f'' = 240x^3+900x^2-720x
f" = 60x(4x^2+15x-12) = 0
x=0, quadratic formula: (-15+-sqrt((-15)^2-4*4*(-12))/(2*4) = (-15+-sqrt(417))/8
Possible POI: x=(-15+sqrt(417))/8, x=0, x=(-15-sqrt(417))/8
[x~~ -4.43, x=0, x~~ 0.678]
Check it is actually POI or not:
f"(-5) = -3900 <0, f"(-1)=1380>0, f"(1)=420<0 , f"(5)=48900>0
Implies all of them are POI
hence x=(-15+sqrt(417))/8, x=0, x=(-15-sqrt(417))/8
[x~~ -4.43, x=0, x~~ 0.678]
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