
Yefim S. answered 07/26/24
Math Tutor with Experience
f(x) = 5/2 + 5/2cos2x; f(0) = 5; f'(x) = - 5sin2x; f'(0) = 0; f''(x) = -10cos2x; f''(x) = -10; f'''(x) = 20sin2x; f'''(0) = 0
fiv = 40cos2x; fiv(0) = 40; fv = - 80sin2x; fv(0) = 0; fvi(x) = -160cos2x; fvi(0) = -160
f(x) = 5 - 10x2/2! + 40x4/4! - 160x6/6! + ... = 5 - 5x2 + 5/3x4 - 2/9x6 + ...