Mark M. answered 04/02/15
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Retired math prof. Very extensive Precalculus tutoring experience.
Let A(t) = amount in t years
P = principal (initial investment)
r = annual interest rate as a decimal
n = number of times that interest is compounded per year
Then, A(t) = P(1 + r/n)nt
Substituting in the given values, we have
637803 = 80000(1 + r/12)360
7.9725375 = (1 + r/12)360
ln(7.9725375) = ln(1 + r/12)360
ln(7.9725375) = 360ln(1 + r/12)
.00576667 = ln(1 + r/12)
1 + r/12 = e0.00576667
1 + r/12 = 1.005783334
r/12 = 0.005783334
r = 0.0694 = 6.94%