I cannot figure out how to get x from this problem. Thanks a lot!

f(x) =9X

^{2}+18X + 5 First check factorability of the quadratic, find out whether there exist 2 integers , a, b, such that

their Sum equals 18, and their product is 9*5 =45

To do that :

Write 45 as product of its factors: 45 = 3 * 15 = 9 * 5

Observe that 3+ 15 =18

f(X) = 9X

^{2 }+15X + 3X +5 /Break up 18X = 15X +3X 3X(3X + 5 ) +(3x +5) / factor the quadratic by grouping

( 3X + 5 )( 3X + 1) =0

^{ }3X + 5 = 0 X = -5/3

3X + 1 = 0 X = -1/3

In the event if, in quadratic aX

^{2 }+ bX +c there is no 2 integers , m;n, does not exist such that m.n= ac and m+n = b

Then to solve the quadratic you can either use factoring by completing square or

using quadratic formula.