Inactive Tutor answered 07/26/24
Power series for x6/(1+x7) = x6∑infn=0(-1)n(x7)n ≈ x6-x13+x20 -+.... = g(x)
∫0.30g(x) dx = x7/7-x14/14+x21/21|0.30≈(0.3)7/7-(0.3)14/14+(0.3)21/21-+....
Approximately (0.3)7/7 ≈ 0.0000312
Rozhan F.
asked 07/26/24Use a power series to approximate the definite integral, I, to six decimal places.
∫ (from 0 to 0.3) x6 / (1+ x7) dx
i = ?
Inactive Tutor answered 07/26/24
Power series for x6/(1+x7) = x6∑infn=0(-1)n(x7)n ≈ x6-x13+x20 -+.... = g(x)
∫0.30g(x) dx = x7/7-x14/14+x21/21|0.30≈(0.3)7/7-(0.3)14/14+(0.3)21/21-+....
Approximately (0.3)7/7 ≈ 0.0000312
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