Mark M. answered 07/26/24
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
1 / (1-x) = sum of geometric series with a = 1 and r = x
= ∑(n=0 to ∞) arn = 1 + x + x2 + x3 + ...
So, d/dx[1 /(1-x)] = 1/(1-x)2 = 1 + 2x + 3x2 + ...
Multiply by 8+x: (8+x)/(1-x)2 = 8[1/(1-x)2] + x[1/(1-x)2]
= 8(1 + 2x + 3x2+ ...) + x(1 + 2x + 3x2 + ...)
= 8 + 17x + 26x2 + 35x3 + ... (note that 8, 17, 26, 35, ...is arithmetic)
So, (8+x) / (1-x)2 = ∑(n=1 to ∞)(9n-1)xn-1, or equivalently,
∑(n=0 to infinity) (9n+8)xn.