Mark M. answered 07/05/24
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Let f(x) = 7x2, 0 ≤ x ≤ 1
Divide the interval [0,1] into n equal subintervals each of width Δx = 1/n.
Using left endpoints, the Riemann Sum approximation for ∫(0 to 1)f(x)dx is :
∑(i = 1 to n) [7((i-1)/n)2(1/n)] = ∑(i= 1 to n) [7(i-1)2 / n3]
limn→∞ ∑(I=1 to n) [7(i-1)2/n3] = ∫(0 to 1) 7x2dx = (7/3)x3(0 to 1) = (7/3)(1 - 0) = 7/3