Stephenson G. answered 06/28/24
Experienced Calculus Tutor: College, AP Calculus AB, AP Calculus BC
To find the point(s) on the parametric curve where the tangent line has a slope of 1/2, calculate dy/dx and set it equal to 1/2.
dx/dt = 12t
dy/dt = 3t2
dy/dx = 3t2/12t = t/4
Set dy/dx equal to 1/2:
t/4 = 1/2
t = 2
After substituting t = 2 back into the parametric equations x(t) and y(t), you get:
x = 29
y = 1
Therefore, the point on the curve where the tangent line has a slope of 1/2 is: (x,y) = (29,1)
Hope this was helpful.
Rozhan F.
sorry I think I typed wrong. The slope should be 1/2.06/28/24