One card is randomly drawn from a standard deck of cards what is the probability of choosing an even number or a diamond

Answer 1

P(E v D) = P(E) + P(D) - P(E^D) = 20/52 + 13/52 - 5/52

if you consider "even" as just 2, 4, 6, 8 and 10, then there are 20 even cards

5 of them are diamonds

P(EvD) = (20+13-5)/52 = 28/52 = 7/13

= .538461538461538461...

= about 54% chance

but you might consider the queen with value of 12 as an even card

A usually = 1, but it could be 14, it ranks 2 above a queen

2 Jokers can be even and/or diamonds

Answer 2

Hi Diana,

Basic equation for this is:

P(A or B) = P(A) + P(B) - P(A and B)

Event A = Even card is drawn

Event B = Diamond is drawn

P(A) = Probability of Even = 20/52 —5 even cards per suit, 4 suits—multiply together

P(B) = 13/52 —13 diamonds in 52 card deck

P(A and B) = 5/52 —5 even diamonds in 52 card deck

So:

P(A or B) = (20/52) + (13/52) - (5/52)

P (A or B) = 28/52

Reduced form:

P(A or B) = 7/13

I hope this helps.