
Dayv O. answered 05/17/24
Caring Super Enthusiastic Knowledgeable Calculus Tutor
let's look at this way
r=[6/sinθ]-1/cosθ
multiply by sinθ
rsinθ=6-tanθ,,,,y/x =rsinθ/rsinθ=tanθ
y=6-(y/x)
y=6x/(x+1)

Franklin S.
asked 05/17/24Dayv O. answered 05/17/24
Caring Super Enthusiastic Knowledgeable Calculus Tutor
let's look at this way
r=[6/sinθ]-1/cosθ
multiply by sinθ
rsinθ=6-tanθ,,,,y/x =rsinθ/rsinθ=tanθ
y=6-(y/x)
y=6x/(x+1)
Raymond B. answered 05/17/24
Math, microeconomics or criminal justice
x=rcosT
x=r/secT
secT/r = 1/x
y = rsinT
y = r/cscT
cscT/r= 1/y
r=6cscT- secT
divide by r
r/r = 1 = 6cscT/r - secT/r
1=6/y -1/x
or
solve for y
multiply by xy
xy = 6x-y
xy+y = 6x
(x+1)y = 6x
y = 6x/(x+1)
f(x) = 6x/(x+1) in functional notation x not =-1
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Adam B.
05/18/24