Let's first convert those secant and cosecant into cosine and sine.
r = 6/sinθ - 1/cosθ
Next, we can divide both sides by r.
1 = 6/r•sinθ - 1/r•cosθ
y = r•sinθ and x = r•cosθ, so let's substitute those in.
1 = 6/y - 1/x
To solve for y, we could first multiply everything by xy to get rid of the fractions. After that, it's just general algebra.
xy = 6x - y
y(x+1) = 6x
y = 6x/x+1
Hope that helps. I know it's been a week since you asked.
Franklin S.
it says domain of the function does not match that of the correct answer05/17/24