Raymond B. answered 04/26/24
Math, microeconomics or criminal justice
y= x^4/5(x-4)^2
y intercept is when x=0
y=0/5(16) = 0
x intercept is when y= 0
0 = x^4/5(x-4)^2
x^4 = 0
x = 0
the x and y intercepts are the origin (0,0)
the domain is all x values that do not make the denominator = 0
5(x-4)^2 = 0
x=4
domain is all real numbers except 4
check the answer
use a graphing calculator
and see where the graph intersects the axes
and where the graph does not have an x value