
Yefim S. answered 04/20/24
Math Tutor with Experience
Elementary work for pumping out section on height x feet from the bottom dW = 2√(100 - x2)·50(10 - x)·62.4·dx;
W = ∫046240(10 - x)√(100 - x2)dx = (x = 10sint; dx = 10costdt) = 6240000∫0arcsin0.4(1 - sint)cos2tdt =
6240000∫0arcsin0.4[(1/2 + cos2t/2)dt + cos2t·d(cost)] = 6240000(t/2 + sin2t/4 + cos3t/3)0arcsin0.4=
6240000(0.59354 - 0.24740) = 2159914 lb·feet