Euler's Method is yn+1 = yn + hyn' = yn + hf(xn,yn) where y' = f(x,y)
1st step y1 = 0 + .5(0 + 2(1)) = 1 starting a y0=0 and x0=1
2nd step y2 1 + .5(1 + 2(1.5)) = 3
and so on.
Lucas S.
asked 04/16/24Use Euler's method with step size 0.5 to compute the approximate y=values y1,y2,y3, and y4 of the solution of the initial-value problem y'=y-2x, y(1)=0
Euler's Method is yn+1 = yn + hyn' = yn + hf(xn,yn) where y' = f(x,y)
1st step y1 = 0 + .5(0 + 2(1)) = 1 starting a y0=0 and x0=1
2nd step y2 1 + .5(1 + 2(1.5)) = 3
and so on.
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