
Yefim S. answered 04/14/24
Math Tutor with Experience
a. F(x) = cot(3x)/3 + C; b. F(x) = - 3tan-1x + C; c. F(x) = - tan(8x)/8 + C; d. F(x) = - e-10x/10 + C
e. F(x) = ∫x3√7 - 6x2dx = (x = √7/6sint; dx = √7/6costdt) = ∫7/6√7/6sin3t7/6cos2tdt = - 49/36√7/6∫cos2t(1 - cos2t)·d(cost).= - 49/36√7/6(cos3t/3 - cos5t/5) + C where cost = (1 - 6/7x2)1/2