#2) Let u = y^3 + 5. Then du = 3y^2du
#3) Let u = 2t^3 + 6t. Then du = (6t^2+6)du = 6(t^2+1)du
Amani G.
asked 04/04/24Use the second fundamental theorem of calculus (and any integration techniques of your choice)
to evaluate the following integrals.
∫10 2x3 + x dx
∫20 y2cos(y3 + 5) dy
∫71 (t2 + 1)/(√2t3 + 6t) dt
#2) Let u = y^3 + 5. Then du = 3y^2du
#3) Let u = 2t^3 + 6t. Then du = (6t^2+6)du = 6(t^2+1)du
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.