Mark M. answered 03/25/24
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Let x(t) = <10t, 5t2, 5lnt>
x(1) = <10, 5, 0> and x(2) = <20, 20, 5ln2>
Arc Length = ∫(1 to 2) √[((10t)')2 + ((5t2)')2 + ((5lnt)')2]dt = ∫(1 to 2)√(100 + 100t2 + 25/t2) dt
= ∫(1 to 2) √[(100t4 + 100t2 + 25) / t2] dt = 5 ∫(1 to 2) √ [(4t4 + 4t2 + 1) / t2]dt
= 5∫(1 to 2) √[(2t2 + 1)2 / t2]dt
= 5∫(1 to 2) [(2t2+1) / t)]dt = 5∫(1 to 2) (2t + 1/t)dt ←Evaluate.