
Bradford T. answered 03/15/24
Retired Engineer / Upper level math instructor
a) ∫5x2-3sin(x)+√3 dx = 5∫x2dx-3∫sin(x)dx+√3∫dx = (5/3)x3+3cos(x)+(√3)x + C
b) ∫ 5√t2/t + 2cos(t) dt = ∫ t2/5/t dt + 2∫cos(t)dt = ∫t-3/5dt + 2∫cos(t)dt =(5/2)t2/5 + 2sin(t) + C
c) let u = 7y2+6y du = (14y+6)dy = 2(7y+3) dy
(-1/2)∫(7y+3)/(7y+3) u-1/3 du = (-1/2)∫u-1/3du = (-1/2)(3/2)u2/3 + C = (-3/4)(7y2+6y)2/3 + C