Yefim S. answered 03/14/24
Math Tutor with Experience
Let h is water level. Then base area B/25 = h2/112; B = 25h2/121; volume V = Bh/3 = 25h3/363;
dV/dt = 25h2/121·dh/dt; dh/dt = 121dV/dt/(25h2) = 121·45cm3/s/(625cm2) = 8.712 cm/s
Emily H.
asked 03/14/24An inverted pyramid is being filled with water at a constant rate of 45 cubic centimeters per second. The pyramid, at the top, has the shape of a square with sides of length 5 cm, and the height is 11 cm.
Find the rate at which the water level is rising when the water level is 5 cm.
Yefim S. answered 03/14/24
Math Tutor with Experience
Let h is water level. Then base area B/25 = h2/112; B = 25h2/121; volume V = Bh/3 = 25h3/363;
dV/dt = 25h2/121·dh/dt; dh/dt = 121dV/dt/(25h2) = 121·45cm3/s/(625cm2) = 8.712 cm/s
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