probability of keyless entry

Question

How many different 5-digit codes can be made using 10 digits if there 5 buttons and 2 digits in each button like this: 1-2, 3-4, 5-6, 7-8, 9-0

Answer 1

If each button has only two numbers, then there are 2*2*2*2*2 = 2⁵ = 32 possibilities.

Answer 2

The problem is not clearly defined.

If you can't repeat digits and 1-2 is different from 2-1, then the answer is the permutations of 10 digits in 10 places i.e. 10! = 3628800