Mark M. answered 03/04/24
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
y = e5√x
Let g(x) = 5√x and f(x) = ex. Then f'(x) = ex and g'(x) = (5/2)x-1/2 = 5 / (2√x).
So f(g(x)) = f(5√x) = e5√x
d/dx[f(g(x))] = f'(g(x))g'(x) = f'(5√x)(5 / (2√x)) = e5√x (5 / 2√x) = (5/2)(e5√x / √x)