
Yefim S. answered 03/01/24
Math Tutor with Experience
Let x times rent increase by $7. Then revenue R(x) = (448 + 7x)(90 - x) = 40320 + 182x - 7x2;
R'(x) = 182 - 14x = 0; x = 182/14 = 13; max R(x) = R(13) = 41503.
Let y times rent decrease by $7 dollars. Then revenue R(y) = (448 - 7y)(90 + y) = 40320 - 182y - 7y2;
R'(y) = - 182 - 14y = 0; y = - 13. So, this means we have to increase rent 13 times and max rent = $41503