Brett S. answered 02/26/24
Experienced College Math Instructor
You have to start by taking the second derivative.
f(x)=sec(x)
f'(x) = sec(x)tan(x) (this should be memorized. The proof isn't bad, but it takes multiplying by an unusual term)
To find the second derivative, you need to remember to use the product rule. d/dx[sec(x)] = sec(x)tan(x) and d/dx[tan(x)] = sec2(x).
f''(x) = [sec(x)tan(x)]•tan(x) + sec(x)•[sec2(x)] (product rule expanded form)
After we get the simplified form f''(x) = sec(x)tan2(x) + sec3(x), we need only to plug π/3 in for x.
f''(π/3) = sec(π/3)tan2(π/3) + sec3(π/3)
f''(π/3) = 2•√32 + 23
f''(π/3) = 14