Mark M. answered 02/25/24
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
g(x) = 5ex√x
Use the product rule:
g'(x) = 5ex√x + 5ex[(1/2)x-1/2] = 5ex[√x + 1/(2√x)] = 5ex[(2x+1) / (2√x)]
Natalie N.
asked 02/25/24g(x) =5e^x√x
Mark M. answered 02/25/24
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
g(x) = 5ex√x
Use the product rule:
g'(x) = 5ex√x + 5ex[(1/2)x-1/2] = 5ex[√x + 1/(2√x)] = 5ex[(2x+1) / (2√x)]
Madison R. answered 02/25/24
3.5 years of experience as a Teaching Assistant for College Calculus
First, note that we can rewrite the original function as g(x)=(5e^x)(x^(1/2)).
The function g(x) is a product of two functions of x, so we need to use the product rule to differentiate g(x). Using basic derivative rules, we get the following:
g'(x)=(5e^x)((1/2)x^(-1/2))+(x^(1/2))(5e^x)
or
g'(x)=(5e^x)(1/(2√x)+√x).
Hope this helps!
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