how fast is the water level rising when the water is 4 feet deep

Question

Water is pouring into a conical tank at the rate of 8 cubic feet per minute. If the height of the tank is 11 feet and the radius of its circular opening is 6 feet, how fast is the water level rising when the water is 4 feet deep?

______ feet per minute

Answer 1

d/h=6/11...r=3h/11 V=(1/3)πr²h=(1/3)π(3h/11)²h

dV/dt=(9h²/121)(dh/dt

Now just plug in the values given in the problem to get dh/dt