Inactive Tutor answered 02/22/24
f(x) = 4x2
The slope of the line is:
f'(x)= 8x
f'(1)=m=8
The tangent line, ℓ, is
y-y0 = m(x-x0)
y-4 = 8(x-1)
y = 8x-4
This line crosses the x-axis at x = 1/2.
At this point, tan(φ) = 4/(1/2) = 8
φ = tan-1(8) ≈ 83°
All G.
asked 02/22/24Let ℓ be the tangent line to the curve y = 4x2
at the point (1, 4). The angle of inclination of ℓ is the angle 𝜑 that ℓ makes with the positive direction of the x-axis. Calculate 𝜑 to the nearest degree.
Inactive Tutor answered 02/22/24
f(x) = 4x2
The slope of the line is:
f'(x)= 8x
f'(1)=m=8
The tangent line, ℓ, is
y-y0 = m(x-x0)
y-4 = 8(x-1)
y = 8x-4
This line crosses the x-axis at x = 1/2.
At this point, tan(φ) = 4/(1/2) = 8
φ = tan-1(8) ≈ 83°
Mark M. answered 02/22/24
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
f(x) = 4x2 f'(x) = 8x
Slope of tangent line at (1, 4) = f'(1) = 8
Angle of inclination = φ = Tan-1(8) = 82.87°
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