
Vansh S. answered 05/05/24
Knowledgeable and Experienced Tutor for Linear Algebra
First, you'd like to turn the system of equations into a coefficient matrix. This will look like:
[1, 1, 0]
[-2, 1, -2]
[7, -3, 8]
Now we can reconsider this question in terms of linear algebra: this problem can be reformulated y = Ax, where A is the coefficient matrix, y is the vector <y1, y2, y3>, and x is the vector <x1, x2, x3>.
The question would like you to solve for x1, x2, x3 in terms of y1, y2, y3. In order to do this, we want to find x = A-1y. You should be able to compute A-1y by means of row reduction on the augmented matrix [A | y], which means that you put the matrix A and the vector y together. The row reduction will yield [ I | A-1 y], where I is the Identity matrix and A-1y is the solution you're interested in.