The derivative is -5/sqrt(9-10x)
At x=-1, the slope is -5/sqrt(19)
The tangent line is -t/sqrt(19)=(y-19)/(x+1)
N.B. I "assumed" that you meant the radical to include the entire expression in your problem.
Natalie N.
asked 02/13/24f(x)= √9-10x
The derivative is -5/sqrt(9-10x)
At x=-1, the slope is -5/sqrt(19)
The tangent line is -t/sqrt(19)=(y-19)/(x+1)
N.B. I "assumed" that you meant the radical to include the entire expression in your problem.
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