To begin, we need to make sure that the function exists at x=2, which it clearly does: f(2) = 2. Next we need to ensure that 1) the limit at any point above 2 exists, 2) the function exists at those points, and 3) that these first two values are equal. To show this let A be any real value in the interval (2, ∞).
1) Limit exists; there is no domain issue that would cause a vertical asymptote or hole in the graph.
limx→A x+√(x-2) = A + √(A-2)
2) The function exists. Same as before, no domain issue causing a lack of existence in the graph.
f(A) = A + √(A-2)
3) Clearly f(A) = limx→A f(x).
So this function is continuous on the interval [2, ∞).