
Dayv O. answered 02/09/24
Caring Super Enthusiastic Knowledgeable Calculus Tutor
in computing function's derivative, will need to know d(cos-1x)/dx
for this piece, cos(cos-1x)=x
d(cos(cos-1x))/dx=1
-sin(cos-1x)*d(cos-1x)dx=1 ,,,,,chain rule for composite function
sin(cos-1x) = (+/-)√(1-x2)
the principle branch for cos-1x is from 0≤cos-1x<π
and the slope of the tangent to the curve is negative in this branch
note: slope of curve is change in cos-1x divided by change in x
where positive change of x is in direction of -1<x≤1
so d(cos-1x)/dx=(-)1/√(1-x2)
for d((cos-1x)/x)/dx use product rule
d((cos-1x)/x)/dx=-[(cos-1x)/x2+(x/x2)*d(cos-1x)/dx
=(-1/x2)[(cos-1x) +x/√(1-x2)]