Mark M. answered 02/06/24
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Δx = width of each interval = (3-0) / 3 = 1
Let f(x) = 4x
Using right endpoints of the three intervals (1, 2, and 3),
Area of first rectangle = f(1)Δx, Area of second rectangle = f(2)Δx, Area of third rectangle = f(3)Δx
∫(0 to 3) 4xdx ≈ f(1)Δx + f(2)Δx + f(3)Δx = 4 + 8 + 12 = 24